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Question

The perimeters of two similar triangles ABC and PQR are 60 cm and 48 cm respectively If PQ=8 cm length of AB is

A
10 cm
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B
8 cm
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C
6 cm
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D
4 cm
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Solution

The correct option is A 10 cm
P1=AB+BC+AC=60cm
P2=PQ+QR+RP=48cm
PQ=8 cm
P1P2=ABPQ
6048=AB8
AB=60×848=10cm

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