Question

The perimeters of two similar triangles ABC and PQR are 60 cm and 48 cm respectively If PQ=8 cm length of AB is

• A. $10cm$
• B. $8cm$
• C. $6cm$
• D. $4cm$

Answer 1

The correct option is A $10cm$

$P_1=AB+BC+AC=60cm$

$P_2=PQ+QR+RP=48cm$

PQ=8 cm

$\frac{P_1}{P_2}=\frac{AB}{PQ}$

$\Rightarrow \frac{60}{48}=\frac{AB}{8}$

$\Rightarrow AB=\frac{60\times 8}{48}=10cm$