Question

The perimeters of two similar triangles are $25$ cm and $15$ cm respectively. If one side of first triangle is $9$ cm, what is the corresponding side of the other triangle?

Answer 1

Let the side of other triangle be $xcm$.

It is given that, two triangles are similar.

$\therefore$ Ratio of the corresponding sides = Ratio of perimeter.

$\therefore$ $\frac{9}{x}=\frac{25}{15}$

$\therefore$ $x=\frac{15\times 9}{25}=5.4cm$

$\therefore$ Side of the other triangle is $5.4cm$