The period of a satellite in a circular orbit of radius R is T, the period of another satellite in a circular orbit of radius 4R is

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T/4

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T/8

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Solution

The correct option is C
8T

$\frac{T_{1}}{T_{2}} = (\frac{R_{1}}{R_{2}})^{\frac{3}{2}} = (\frac{R}{4 R})^{\frac{3}{2}} \Rightarrow T_{2} = 8 T_{1}$

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