Question

The time period of a satellite in a circular orbit of radius $R$ is $T$, the period of another satellite in a circular orbit of radius $4R$ is

• A. $4T$
• B. $T/4$
• C. $8T$
• D. $T/8$

Answer 1

The correct option is C $8T$

$T=\frac{2\pi }{R}{\left[\frac{(R+h{)}^3}{g}\right]}^{1/2}$
Here $(R+h)$ changes from $R$ to $4R$. Hence period of revolution changes from $T$ to $(4^3{)}^{1/2}T=8T$.