The period of a simple pendulum is doubled, when

Its length is doubled

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The mass of the bob is doubled

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Its length is made four times

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The mass of the bob and the length of the pendulum are doubled

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Solution

The correct option is C
Its length is made four times

T = $2 π \sqrt{\frac{l}{g}} \Rightarrow T \propto \sqrt{l}$

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The length of a simple pendulum is made one-fourth. Its time period becomes :

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The period of a simple pendulum is doubled, when

The correct option is C Its length is made four times T = 2π√lg⇒T∝√l

The correct option is C
Its length is made four times

T = $2 π \sqrt{\frac{l}{g}} \Rightarrow T \propto \sqrt{l}$