The period of a simple pendulum measured inside a stationary lift is found to be T. If the lift starts accelerating upwards with acceleration of g/3, then the time period of the pendulum is
A
T√3
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B
T3
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C
√32T
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D
√3T
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Solution
The correct option is A√32T For stationary lift T1=2π√lg For ascending lift with acceleration a,