The period of simple pendulum inside a stationary lift is T. The lift accelerates upward with an acceleration of g/3.The time period of simple pendulum will be

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Solution

T = 2π√lg. When the lift accelerates upwards with an acceleration of ,
the effective acceleration is g' = g+g3=4g3
Therefore, the new time period is
T′=2π√lg′ThusT′T=√gg′=√g4g/3=√32orT′=√32T.

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The period of simple pendulum inside a stationary lift is T. The lift accelerates upward with an acceleration of g/3.The time period of simple pendulum will be

T = 2π√lg. When the lift accelerates upwards with an acceleration of , the effective acceleration is g' = g+g3=4g3 Therefore, the new time period is T′=2π√lg′ThusT′T=√gg′=√g4g/3=√32orT′=√32T.

T = 2π√lg. When the lift accelerates upwards with an acceleration of ,
the effective acceleration is g' = g+g3=4g3
Therefore, the new time period is
T′=2π√lg′ThusT′T=√gg′=√g4g/3=√32orT′=√32T.