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Question

The period of revolution of an earth satellite close to surface of earth is 90 min. The time period of another satellite in an orbit at a distance of three times the radius of earth from its surface will be


A

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B

360 min

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C

720 min

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D

270 min

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Solution

The correct option is C

720 min


Distance of second satellite from the centre of earth has become four times.

Now T2r3 or Tr32

Time period of second satellite will become (4)32 or 8 times.

Hence T'= 8T = (8) (90) = 720 min


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