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Question

The period of revolution of planet A around the sun is 8 times that of B.The distance of A from the sun is how many times greater than that of B from the sun?

1)4

2)5

3)2

4)3

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Solution

Step 1, Given

The period of revolution of planet A around the sun is 8 times that of B

Step 2,

From the Kepler's third law

We know,

T2αr3 Where T is the time period and r is the distance from the sun

We can write

TA2TB2=rA3rB3

After putting all the values

(81)2=rA3rB3

Or,

rArB=4

Or,rA=4rB

Hence radius of A is 4 times the radius of B



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