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Heat of Formation

The pH at whi...

Question

The $p H$ at which $N i (O H)_{2}$ begins to precipitate from a solution containing $10^{- 3} M$ $N i^{2 +}$ ions:
$[K_{s p}$ of $(N i (O H)_{2} = 10^{- 11}]$

p H = 3

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p H = 10

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p H = 13

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p H = 11

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Solution

The correct option is B $p H = 10$
$N i (O H) ⇌ N i^{2 +} + 2 O H^{-}$
$10^{- 3} \times [O H^{-}]^{2} = 10^{- 11}$
$[O H^{-}]^{2} = 10^{- 8}$
$[O H^{-}] = 10^{- 4}$
$p O H = 4$
$p H = 10$

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