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Question

The pH of an aqueous solution containing 0.025 M H2SO4 and 0.005 M HCl is:
log10(5.5)=0.74

A
0.74
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B
1.26
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C
0.26
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D
1.74
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Solution

The correct option is B 1.26
Number of moles of H+ coming from H2SO4 are,
nH+=2×0.025×V
Number of moles of H+ coming from HCl are,
nH+=0.005×V
Here final volume is Vf=V L
So, final concentration of H+ will be:
Cf=(2×0.025×V)+(0.005×V)V =0.055 MpH= log10[0.055]pH= log10[5.5×102]pH=20.74=1.26


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