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Question

The pH of resulting solution after addition of NaCN is:

A
9.86
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B
8.86
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C
6.86
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D
5.86
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Solution

The correct option is A 9.86
HClMole1030+NaCN4×1030.003NaCl00.001+HCN00.001

pH=pKa+log[Conjugate base][Acid]

=9.3872+log0.0030.001=9.8643

Hence, the correct option is A

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