Question

The phase difference between current and voltage in an AC circuit is $\frac{\pi }{4}$ radian. If the frequency of AC is 50 Hz, then the phase difference is equivalent to the time difference:-

• A. 0.78 s
• B. 15.7 ms
• C. 2.5 s
• D. 2.5 ms

Answer 1

The correct option is D 2.5 ms

Phase difference $\Rightarrow \varphi =\pi /4rad$

Frequency $\Rightarrow f=50Hz$

Then,

time difference $\Rightarrow \Delta t=\frac{\varphi }{2\pi f}$

$\Delta t=\frac{\pi /4}{2\pi \times 50}=\frac{1}{400}=0.0025s$

$\Delta t=2.5ms$