The phase difference between the applied emf and the line current in an anti resonant circuit at resonance is

\frac{π}{2}

radian

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π

radian

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\frac{3 π}{2}

radian

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zero

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Solution

The correct option is D zero
We know that phase difference is given by:
$ϕ = arctan (\frac{(X_{L} - X_{c})}{R})$
at resonance
$X_{L} - X_{c} = 0$
Therefore $ϕ = 0$ .

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