The phosphate of a metal has the formula $M H P O_{4}$ , the formula of its chloride would be:

M C l

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M C l_{2}

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M C l_{3}

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M_{2} C l_{3}

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Solution

The correct option is C $M C l_{2}$
$M H P O_{4} ⟶ M^{2 +} + {P O_{4}}^{2 -}$

The valency of $H P O_{4}$ has a valency of $- 2$ .

Therefore, the valency of metal has a valency of $+ 2$ .

$M^{2 +} + 2 C l^{-} ⟶ M C l_{2}$

Option B is correct .

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Similar questions

M H P O_{4}

A metal sulphate has the formula MSO4. A cloride of the same metal will have the formula

(A)M2cl3

(B)M2cl

(C)Mcl2

(D)Mcl

H_{3} P O_{4}

M C l_{2}

M

M {C l}_{3}

M

M C l, M {C l}_{2}, M {C l}_{3}

M C l > M {C l}_{2} > M {C l}_{3}

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