Question

The pillars of a temple are cylindrical shaped. If each pillar has a circular base of radius $25cm$ and height $10.5m$, then find the quantity of concrete mixture used to build $32$ such pillars. Also find the cost of the concrete mixture at the rate of $Rs.250$ per $m^3$. (take $\pi =22/7$)

Answer 1

Volume of the cylinder$=\pi r^{2}h$

$=\pi \times 0.25\times 0.25\times 10.5$

$=\frac{22}{7}\times 0.25\times 0.25\times 10.5$

$=2.0625c{m}^3$

$\therefore$ Volume required to build each pillar$=2.0625m^3$

Now the total number of pillars$=32$

Total volume of concrete required$=32\times 2.0625$$=66$

Rate$=$ Rs. $250/m^3$

$\therefore$ Total cost$=66\times 250$$=$Rs. $16500$.