Question

The pillars of a temple are cylindrically shaped. Each pillars has a circular base of radius $20cm$ and height $10cm$. How much concrete mixture would be required to build $14$ such pillars?

Answer 1

Considering it to a solid cylinder, for amount of concrete making are cylinder $=$ volume of cylinder

$\therefore$ Amount of concrete mixture required to fild $14$ such pillars $=14\times$ volume of a cylinder$-----\left(1\right)$

If Volume of cylinder where $=\pi r^{2}h$

$x=radius$

$h=height$

Volume $=\pi \times x^2\times h$

$=\pi \times 20\times 20\times 10c{m}^3$

$=4000\pi c{m}^3$

$=4000\times 3.142c{m}^3$

$=12568c{m}^3$

Substituting it in equation $\left(1\right)$

$=14\times 12568$

$=150816c{m}^3$

$\therefore$ Amount of concrete mixture required to build $14$ such pillars $=150816c{m}^3$