Question

The pillars of a temple are cylindrically shaped. If each pillar has a circular base of radius $20cm$ and height $10m$. How much concrete mixture would be required to build $14$ such pillars?

Answer 1

Given data is as follows:

$r=20cm=0\cdot 2m$

$h=10m$

Number of pillars $=14$

We have to find the total amount of concrete present in all $14$ pillars.

Radius of the pillar is given in centimeters, so let us convert it to meters.

Let us first find the amount of concrete present in one pillar, which is nothing but the volume of the pillar.

Volume of $1$ pillar $=\pi r^{2}h$

$=\pi \times 0\cdot 2\times 0\cdot 2\times 10$

Volume of $14$ pillars$=14\times \pi \times 0\cdot 2\times 0\cdot 2\times 10$

$=14\times \frac{22}{7}\times 0\cdot 2\times 0\cdot 2\times 10$

$=17\cdot 6m^3$

Therefore, total amount of concrete mixture in $14$ pillars is $17\cdot 6m^3$.