Question

The plane $\frac{x}{2}+\frac{y}{3}+\frac{z}{1}=1$ meet the co-ordinate axis at the points $A,B,C$ respectively then the area bounded by the triangle $ABC$ is

• A. $6$ sq. units
• B. $\frac{9}{2}$ sq.units
• C. $\frac{5}{2}$ sq.units
• D. $\frac{7}{2}$ sq.units

Answer 1

The correct option is D $\frac{7}{2}$ sq.units

$A=(2,0,0)$
$B=(0,3,0)$
$C=(0,0,1)$
$\overrightarrow{AB}=(-2,3,0)$
$\overrightarrow{AC}=(-2,0,1)$

Area of triangle

$=\frac{1}{2}\overrightarrow{(}AB\times \overrightarrow{AC})$

$=\frac{7}{2}$ sq units