The point charges -2q, -2q, and +q are put on the vertices of an equilateral triangle of side a. Find the work done by some external force in increasing the separation to 2a (in joules)
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Solution
Here work done ,W=Wf−Wi Wi=k(−2q)(−2q)a+k(−2q)(q)a+k(q)(−2q)a=k4q2a−k4q2a=0 Wf=k(−2q)(−2q)2a+k(−2q)(q)2a+k(q)(−2q)2a=k4q22a−k4q22a=0 ∴W=0