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Question

The point on the line x21=y+32=z+52 at a distance of 6 from the point (2, -3, -5) is

A
(3, -5, -3)
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B
(4, -7, -9)
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C
(0, 2, -1)
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D
(-3, 5, 3)
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Solution

The correct option is B (4, -7, -9)
DC’s of the given line is 13,23,23
Hence, the equation of line can be point in the form x213=y+323=z+523=r
Point is (2+r3,32r3,52r3)
r=±6
Points are (4, -7, -9) and (0, 1, -1)

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