The point on the line x-2-1-y-3-2-z-5-2-r say at a distance of 6 units from the point 2-3-5 is

The correct option is B (4, –7, –9)DC’s of the given line is 1/3, 2/3, 2/3 Hence, the equation of line can be point in the form x 2/1/3 = y+3/ 2/3 = z 5/ 2/ ...

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Standard XII

Mathematics

Equation of Line: Symmetrical Form

The point on ...

Question

The point on the line $\frac{x - 2}{1} = \frac{y + 3}{- 2} = \frac{z - 5}{- 2} = r (s a y)$ at a distance of 6 units from the point (2, –3, 5) is

(3, –5, –3)

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(4, –7, –9)

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(0, 2, –1)

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(3, 2, 1)

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Solution

The correct option is B (4, –7, –9)
DC’s of the given line is
$\frac{1}{3}, - \frac{2}{3}, - \frac{2}{3}$
Hence, the equation of line can be point in the form
$\frac{x - 2}{\frac{1}{3}} = \frac{y + 3}{\frac{- 2}{3}} = \frac{z - 5}{\frac{- 2}{3}} = r ∴ P o i n t i s (2 + \frac{r}{3}, - 3 - \frac{2 r}{3}, - 5 - \frac{2 r}{3}) r = \pm 6$
Points are (4, –7, –9) and (0, 1, –1)

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