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Question

The point on x-axis which is equidistant from points A(−1, 0) and B(5, 0) is [CBSE 2013]
(a) (0, 2) (b) (2, 0) (c) (3, 0) (d) (0, 3)

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Solution

Let P(x, 0) the point on x-axis, then
AP=BPAP2=BP2x+12+0-02=x-52+0-02x2+2x+1=x2-10x+2512x=24x=2
Thus, the required point is (2, 0).
Hence, the correct answer is option (b).

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