The points (1,−2),(−2,−1),(4,7) and (6,3) are concyclic.
Four pointsA(6,3),B(−3,5),C(4,−2)and D(x,3x)are given in such a way thatΔ DBCΔ ABC=12,find x.
A (6, 3), B (−3, 5), C (4, −2) and D (x, 3x) are four points. If Δ DBC:ΔABC=1:2, then x is equal to
Four points A (6, 3), B (-3, 5), C (4, -2) and D (x, 3x) are given in such a way that △DBC△ABC=12,find x.