The points (5, - 2), (6, 4) and (7, - 2) are the vertices of an _________ triangle.
[3]
Let the points (5, - 2), (6, 4) and (7, - 2) represent the vertices A, B, and C of the given triangle respectively.
Distance between the points is given by
√(x1−x2)2+(y1−y2)2
AB=√(5−6)2+(−2−4)2
=√(−1)2+(6)2
=√1+36=√37
[1]
BC=√(6−7)2+(4−(−2))2
=√(−1)2+(6)2
=√1+36=√37
[1]
AC=√(5−7)2+(−2(−2))2
=√(−2)2+02=2
[1]
⇒ AB = BC
As two sides are equal in length, therefore, ABC is an isosceles triangle.