The points of extremum of the function Fx - -1x e-t2-2 1-t2 dt are

F'(x) = e^ x^2/2 (1 x^2) =0 ∴ x = ± 1 ...

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Extrema

The points of...

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The points of extremum of the function $F (x) = \int_{1}^{x} e^{- t^{2} / 2} (1 - t^{2})$ dt are

\pm 1

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\pm \frac{1}{2}

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\pm 2

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ϕ (x) = \int_{1}^{x} e^{- \frac{t^{2}}{2}} (1 - t^{2}) d t

The points of extremum of the function $F (x) = \int_{1}^{x} e^{- t^{2} / 2} (1 - t^{2})$ dt are

F (x) = \int_{1}^{x} e^{- t^{2 / 2}} (1 - t^{2}) d t

x

f (x) = \int_{0}^{x} (1 - t^{2}) e^{- t^{2} / 2} d t

I f G = \int_{2}^{x^{2}} \frac{1}{l n (1 + t^{2})} d t

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