The polar of the point $(2, 1)$ with respected to the parabola $y^{2} = 6 x$ , is

y = 3 x + 2

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y = 3 x + 6

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3 y = x + 6

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y = 3 x + 4

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Solution

The correct option is B $y = 3 x + 6$
The required polar is given by,
$T = 0 \Rightarrow y y_{1} = \frac{6}{2} (x + x_{1})$
$\Rightarrow y = 3 (x + 2) = 3 x + 6$

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