The polars drawn from -1-2 to the circle s S1- x2-y2-6 y-7-0 and S2- x2-y2-6 x-1-0- areA- EqualB- PerpendicularC- ParallelD- Intersect at a point

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Pole and Polar of a Circle

The polars dr...

Question

The polars drawn from (-1,2) to the circle s $S_{1} \equiv x^{2} + y^{2} + 6 y + 7 = 0$ and $S_{2} \equiv x^{2} + y^{2} + 6 x + 1 = 0$ , are

Parallel

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Equal

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Perpendicular

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Intersect at a point

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Solution

The correct option is D
Intersect at a point

The equation of polar to circle (i) is $x - 5 y + 13 = 0$

and equation of polar to circle (ii) is $x + y - 1 = 0$

Clearly, polars intersect at a point.

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The polars drawn from (-1,2) to the circle sS1≡x2+y2+6y+7=0 and S2≡x2+y2+6x+1=0, are

The correct option is D Intersect at a point The equation of polar to circle (i) is x−5y+13=0 and equation of polar to circle (ii) is x+y−1=0 Clearly, polars intersect at a point.

The polars drawn from (-1,2) to the circle s $S_{1} \equiv x^{2} + y^{2} + 6 y + 7 = 0$ and $S_{2} \equiv x^{2} + y^{2} + 6 x + 1 = 0$ , are

The correct option is D
Intersect at a point

The equation of polar to circle (i) is $x - 5 y + 13 = 0$

and equation of polar to circle (ii) is $x + y - 1 = 0$

Clearly, polars intersect at a point.