The pole strength of a bar magnet is 2 Am. If the field at poles are 0.2 T and 0.22 T, then the force acting on the bar magnet is
( consider field direction to be same)

0.4N

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0.04N

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0.44N

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0.8N

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Solution

The correct option is C 0.04N
$m = 2 A m$ (given)
$B n e t = B_{2} - B_{1}$
$= 0.22 - 0.2$
$= 0.02 T$
$F = m B n e t$
$= 0.04 N$

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The pole strength of a bar magnet is 2 Am. If the field at poles are 0.2 T and 0.22 T, then the force acting on the bar magnet is( consider field direction to be same)

The correct option is C 0.04Nm=2Am (given)Bnet=B2−B1=0.22−0.2=0.02TF=mBnet=0.04N

The pole strength of a bar magnet is 2 Am. If the field at poles are 0.2 T and 0.22 T, then the force acting on the bar magnet is
( consider field direction to be same)

The correct option is C 0.04N
$m = 2 A m$ (given)
$B n e t = B_{2} - B_{1}$
$= 0.22 - 0.2$
$= 0.02 T$
$F = m B n e t$
$= 0.04 N$