Question

The population of a town increases 10% annually. If it's present population is 60000 what will be it's population after 2 years

Answer 1

Present population $=60000$
Increase in population in 1 year
$=10\%$ of $60000$
$=\left(\frac{10}{100}\right)\times 60000$
$=6000$
Thus, population after 1 year $=60000+6000=66000$

Now, population after 2 years $=66000+10\%\times 66000$

$=66000+6600$

$=72,600$

Therefore, population after 2 years is $72,6000$