The annual increase in the population of a town is 10%. If the present population of the town is 180,000, then what will be its population after two years ?

200,000

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210,000

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217,800

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207,800

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Solution

The correct option is C 217,800
Population after 1 year $= 180000 + 180000 \times \frac{10}{100} = 198000$
Population after 2 years $= 198000 + 198000 \times \frac{10}{100}$
$= 217800$

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