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Question

The annual increase in the population of a town is 10%. If the present population of the town is 180,000, then what will be its population after two years ?


A
200,000
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B
210,000
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C
217,800
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D
207,800
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Solution

The correct option is C 217,800
Population after 1 year $$= 180000 + 180000\times \dfrac{10}{100} = 198000$$ 
Population after 2 years $$ = 198000 + 198000\times \dfrac{10}{100}$$ 
                                              $$=217800$$

Mathematics

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