CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

If the population of a town is $$64000$$ and its annual increase is $$10\%$$, then its correct population at the end of $$3$$ years will be


A
8000
loader
B
85000
loader
C
85100
loader
D
85184
loader

Solution

The correct option is D $$85184$$
Population at the end of $$3$$ years.
$$= 64000{ \left( 1+\cfrac { 10 }{ 100 }  \right)  }^{ 3 }$$ 
$$=64000\times \cfrac { 11 }{ 10 } \times \cfrac { 11 }{ 10 } \times \cfrac { 11 }{ 10 }$$
$$ =85184$$

Maths

Suggest Corrections
thumbs-up
 
0


similar_icon
Similar questions
View More


similar_icon
People also searched for
View More



footer-image