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Question

The population of a town increases 10% annually. If its present population is 60000, what will be its population after 2 years?


Solution

Present population of the town =60000
Increase in population of the town after the 1 year =10% of 60000
=10100×60000
=6000
Thus, population of the town after 1 year
 =60000+6000
=66000
Increase in population after 2 years
=10% of 66000
=10100×66000
=6600
Thus, population after the second year =66000+6600=72600
Hence, the population of the town after 2 years will be 72600.


Mathematics
RS Aggarwal (2017)
Standard VII

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