Question

The population of a town increases $10\%$ annually. If its present population is $60000$, what will be its population after $2$ years?

Answer 1

Present population of the town $=60000$
Increase in population of the town after the $1$ year $=10\%$ of $60000$
$=\frac{10}{100}\times 60000$
$=6000$
Thus, population of the town after $1$ year
$=60000+6000$
$=66000$
Increase in population after $2$ years
$=10\%$ of $66000$
$=\frac{10}{100}\times 66000$
$=6600$
Thus, population after the second year $=66000+6600=72600$
Hence, the population of the town after $2$ years will be $72600$.