Question

The population of a town increases by 10% annually. If the present population is 60000, what will be its population after 2 years?

Answer 1

Present population of the own =60000

Increase annually =10%

Period =2 years

$\therefore$ Population after 2 years will be

$=60000\frac{(100+10)}{100}\times \frac{(100+10)}{100}$

$=60000\times \frac{110}{100}\times \frac{110}{100}$

=72600