The population of a town increases from $1, 60, 000$ to $1, 80, 000$ in a year. Find the percentage increase in the population of the town.

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Solution

Increase in population $= 1, 80, 000 - 1, 60, 000 = 20, 000$
Percentage increase $= \frac{20, 000}{1, 60, 000} \times 100 = \frac{100}{8} = 12.5 %$
Hence the percentage increase in the population of the town is $12 %$ .

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