Question

The population of a village has a constant growth of $5$% every year. If its present population is $1,04,832$, what was the population two years ago?

Answer 1

Let $P$ be the population two years ago.
$\therefore$ $P{(1+\frac{5}{100})}^2=104832$
$P{\left(\frac{105}{100}\right)}^2=104832$
$P\times \frac{105}{100}\times \frac{105}{100}=104832$
$P=\frac{104832\times 100\times 100}{105\times 105}$
$=95085.71$
$=95,086$ (rounding off to the nearest whole number)
$\therefore$ Two years ago the population was $95,086$.