Question

The population of city increases each year by 4% of what it had been at the beginning of each year. If its present population is 6760000, find :

1) its population 2 years hence

2) its population 2 years ago

Answer 1

Population increase=4%
present population= 6760000
1. 4%of 6760000
4/100*6760000 =27040
6760000+27040=6787040
6787040+(4/100*6787040)=7058522(approx)
(population after 2 years hence)
present population= 6760000
4% of 6760000=27040
6760000-27040= 6732960
4% of 6732960=269318.4
6732960-269318.4
=6463642(approx)
population 2 years ago

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