Question

The population of small town is increased by $\frac{15}{2}$% per annum for two years. If the present population is 73,960, then two years before the population was

• A. 68,000
• B. 70,000
• C. 64,000
• D. 60,000

Answer 1

The correct option is C 64,000

Given that:

Current population $=73,960$, Decreasing rate $=7.5\%$, Time $t=2$ years

Let the population be $x$ before two years then

$x=73,960\times (1+\frac{7.5}{100}{)}^2$

$x=73,960\times (1+.075{)}^2$

$x=64,000$

This is the required solution.