The portion of a line intercepted between the co-ordinate axes is bisected at the point (2,4) the equation of the line is

2x+y=6

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x+2y=6

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2x+y=8

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x+2y=8

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Solution

The correct option is B 2x+y=8
$\begin{matrix} \frac{h}{2} = 2, \frac{k}{2} = 4 h = 4, k = 8 \frac{x}{h} + \frac{y}{k} = 1 \frac{x}{4} + \frac{y}{8} = 1 2 x + y = 8 H e n c e, o p t i o n C i s c o r r e c t a n s w e r . \end{matrix}$

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The portion of a line intercepted between the co-ordinate axes is bisected at the point (2,4) the equation of the line is

The correct option is B 2x+y=8h2=2,k2=4h=4,k=8xh+yk=1x4+y8=12x+y=8Hence,optionCiscorrectanswer.

The correct option is B 2x+y=8
$\begin{matrix} \frac{h}{2} = 2, \frac{k}{2} = 4 h = 4, k = 8 \frac{x}{h} + \frac{y}{k} = 1 \frac{x}{4} + \frac{y}{8} = 1 2 x + y = 8 H e n c e, o p t i o n C i s c o r r e c t a n s w e r . \end{matrix}$