Given,
Trajectory of motion of particle is x=1+t−t2. So, this is the parabolic equation.
So, differentiate x with respect to time
dxdt=0+1−2t
0=1−2t
⇒t=12=0.5
At t=0. , we have to check $\dfrac{d^2x}{dt^2}.
Now, again differentiate $\dfrac{dx}{dt} with respect to t
d2xdt2=−2 Which is <0
Hence, at t=0.5, particle reaches maximum velocity and also chanhinf the nature of motion [ after t=0.5 , particle is retardating ]
So, total distance can be found by
S=|x(t=0.5)−x(t=0)|+|x(t=2)−x(t=0.5)|
=|1+0.5−0.25−1|+|1+2−4−1−0.5+0.25|
=0.75+|−2−0.25|
=0.75+2.25
=3m.