The position of a particle is given by →r=3t^i+√3t2^j−4^k where t is in seconds and →r is meters. Find out magnitude of velocity →v and angle made by velocity →v with X-axis at t=√3s.
A
3√5m/s,θ=tan−1(2)
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B
3√5m/s,θ=tan−1(2√3)
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C
3√2m/s,θ=tan−1(3)
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D
3√5m/s,θ=tan−1(1√2)
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Solution
The correct option is A3√5m/s,θ=tan−1(2) It is given that the position vector →r=3t^i+√3t2^j−4^k.
We know that velocity is derivative of position with respect to time,