The position vectors of three consecutive vertices of a parallelogram are $i + j + k, i + 3 j + 5 k$ and $7 i + 9 j + 11 k$ . The position vector of the fourth vertex is

6 (i + j + k)

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7 (i + j + k)

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2 j - 4 k

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6 i + 8 j + 10 k

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Solution

The correct option is B $7 (i + j + k)$
Position vector of fourth vertex is:
$= 7 i + 9 j + 11 k + (i + j + k - i - 3 j - 5 k)$
$= 7 i + 9 j - 2 j + 11 k - 4 k$
$= 7 (i + j + k)$
$∴$ The required position vector is $7 (i + j + k)$

Suggest Corrections

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