The position vectors of two balls are given by r-1- 2mi - 7mj r-2- -2mi - 4mjWhat will be the distance between the two balls-

Displacement vector of two balls #160; r⃗ #160; _ 1 r⃗ #160; _ 2 r⃗_1 r⃗ #160; _ 2 =4î +3ĵ ∴ #160; distance #160; d=| r⃗ #160 ...

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Standard XII

Physics

Vector Addition

The position ...

Question

The position vectors of two balls are given by
${\to r}_{1} = 2 (m) i + 7 (m) j$
${\to r}_{2} = - 2 (m) i + 4 (m) j$
What will be the distance between the two balls?

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Solution

Displacement vector of two balls ${\to r}_{1} - {\to r}_{2}$
${\to r}_{1} - {\to r}_{2} = 4^i + 3^j$
$∴$ distance $d = | {\to r}_{1} - {\to r}_{2} | = \sqrt{16 + 9} = \sqrt{25} = 5$

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The position vectors of two balls are given by→r1=2(m)i+7(m)j→r2=−2(m)i+4(m)jWhat will be the distance between the two balls?

Displacement vector of two balls →r1−→r2→r1−→r2=4^i+3^j∴ distance d=|→r1−→r2|=√16+9=√25=5

The position vectors of two balls are given by
${\to r}_{1} = 2 (m) i + 7 (m) j$
${\to r}_{2} = - 2 (m) i + 4 (m) j$
What will be the distance between the two balls?

Displacement vector of two balls ${\to r}_{1} - {\to r}_{2}$
${\to r}_{1} - {\to r}_{2} = 4^i + 3^j$
$∴$ distance $d = | {\to r}_{1} - {\to r}_{2} | = \sqrt{16 + 9} = \sqrt{25} = 5$