The positive number x that exceeds its square by largest amount is

\frac{1}{2}

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\frac{1}{3}

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\frac{1}{4}

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Solution

The correct option is B $\frac{1}{2}$
$f (x) = x - x^{2}$
$f^{'} (x) = 1 - 2 x$
$x = \frac{1}{2}$ when $f^{'} (x) = 0$

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The positive number x that exceeds its square by largest amount is

The correct option is B 12f(x)=x−x2f′(x)=1−2xx=12 when f′(x)=0

The correct option is B $\frac{1}{2}$
$f (x) = x - x^{2}$
$f^{'} (x) = 1 - 2 x$
$x = \frac{1}{2}$ when $f^{'} (x) = 0$