Question

The possible correct set of quantum numbers for the unpaired electron of $Cl$ atom is

• A. $2,0,0,+\frac{1}{2}$
• B. $2,1,-1,+\frac{1}{2}$
• C. $3,1,1,-\frac{1}{2}$
• D. $3,0,0,+\frac{1}{2}$

Answer 1

The correct option is C $3,1,1,-\frac{1}{2}$

The electronic configuration of $Cl$ atom is $\left[Ne\right]3s^{2}3p^5$. The unpaired electron is present at $p-$orbital for which $n=3,l=1,m=-1,0,+1$ and $s=\pm \frac{1}{2}$
So, possible set can be $3,1,1,-\frac{1}{2}$