The potential difference across the terminals of a battery is 50V when 11A are drawn and 60V when 1A is drawn. The emf and the internal resistance of the battery are
A
62V;2Ω
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B
63V;1Ω
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C
61V;1Ω
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D
64V;2Ω
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Solution
The correct option is B 61V;1Ω ⇒E−11r=50 E−r=60 ⇒10r=10 r=1Ω E=61V