The potential difference across the terminals of a battery is 50V when 6A of current is drawn and 60V when 1A is drawn. The emf and internal resistance of the battery are
A
62V, 2Ω
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B
63V, 1Ω
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C
61V, 1Ω
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D
64V, 2Ω
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Solution
The correct option is A 62V, 2Ω V= E - Ir 50 = E - 6r → (1) 60 = E - 1r → (2) (2) - (1) 10 = 5r; r = 2Ω E = 62V