The potential difference applied to an X-ray tube is 5 KV and the current through it is 3.2 mA. Then the number of electrons striking the target per second is
A
2×1016
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B
5×106
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C
1×1017
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D
4×1015
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Solution
The correct option is A2×1016 i=qt=net⇒n=ite=3.2×10−3×11.6×10−19=2×1016