Question

The potential due to charged spherical shell of radius 20 cm at a point 5 cm distance from the center is v the potential on the surface of the spherical shell is.

Answer 1

Step 1, Given data

The radius of the shell = 20 cm

Distance of the point = 5 cm

Potential at the point = v

Step 2, Finding the potential at the surface

We know,

For any charged spherical shell

$V_{inside}=V_{surface}=\frac{Kq}{R}$

According to the question distance of the point is 5 cm it means that it is inside the shell

So,

$V_{inside}=V_{surface}=v$

Hence the potential at the surface is v.