The potential energy for a force field ¯F is given by ∪(x,y) = cos(x+y). The force acting on a particle at position given by coordinates (0, π/4) is
Fx = - ∂∪∂χ = sin(x + y) = 1√2
Fy = - ∂∪∂γ = sin(x + y) = 1√2
¯F = 1√2 [^i+^j]